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FIELD NOTES

How to Calculate Raffle Odds With Multiple Prizes

Why your ticket share times the prize count is not the probability of at least one win.

Start with the draw rules

Count every ticket in the final pool, including your own. Suppose N tickets exist, K are yours and d winning tickets are drawn fairly without replacement. Each ticket can win once; one person may hold several winning tickets.

Use the chance of no wins

There are C(N,d) possible sets of winners and C(N − K,d) sets with none of your tickets. So your chance of at least one prize is 1 − C(N − K,d)/C(N,d). The tool evaluates the ratio with logarithms to reduce numerical overflow.

For 5 tickets out of 500 and 3 prizes, the no-win probability is (495/500) × (494/499) × (493/498). The win probability is about 2.98%.

Expected prizes are not win probability

d × K/N is the average prize count. It can exceed one. A probability cannot exceed one, and someone may win multiple prizes, so the two measures are not interchangeable. Removing a winner’s remaining tickets changes the rules and is not included in this model.

A larger pool changes your odds

If entries are still open, results are conditional on the total you enter. A current entry count is not a final promise. Use the final total when it is available.

Put the idea to work

Pull odds · Raffle odds · Custom pity · Tries for a target chance